# Dividing whole variable to a fraction with a variable

I have this expression

Using distributive property, It became like this

How did it arrived at $-4a^{-1}a^{1/3}$ ?

• Do you mean $-4a^{-1}a^{1/3}$ is (part of) the given answer? It is wrong. – StackTD Jan 12 '17 at 8:56
• @StackTD Not part of the given answer but the previous step before we arrive with the final answer – KyelJmD Jan 13 '17 at 1:45

by multiplication we get $$2a^{2+1/2}-4a^{-1+1/2}$$ using the power rule we get $$2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}$$

• You inadvertently left out the $a$ in the first term. Should be $2a^\frac{5}{2}$ – scott Jan 12 '17 at 22:24