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I have this expression

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Using distributive property, It became like this

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How did it arrived at $-4a^{-1}a^{1/3}$ ?

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    $\begingroup$ Do you mean $-4a^{-1}a^{1/3}$ is (part of) the given answer? It is wrong. $\endgroup$ – StackTD Jan 12 '17 at 8:56
  • $\begingroup$ @StackTD Not part of the given answer but the previous step before we arrive with the final answer $\endgroup$ – KyelJmD Jan 13 '17 at 1:45
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by multiplication we get $$2a^{2+1/2}-4a^{-1+1/2}$$ using the power rule we get $$2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}$$

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  • $\begingroup$ You inadvertently left out the $a$ in the first term. Should be $2a^\frac{5}{2}$ $\endgroup$ – scott Jan 12 '17 at 22:24

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