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How do i solve this one using exponential function? should i bring up x^2? $$\int\frac{2^{\frac{1}{x}}}{x^2}dx$$

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  • $\begingroup$ U-subsitution is a nice way to proceed, do you see anything in the integrand that would be useful to set equal to u? $\endgroup$ – mike van der naald Jan 11 '17 at 5:09
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$$t=(1/x)$$,$$-dt=\frac{dx}{x^2}$$$$\int2^tdt=\frac{2^t}{\ln2} +C$$

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  • $\begingroup$ why the derivative of t become negative? and became x^2? $\endgroup$ – Kilik Sky Jan 11 '17 at 5:21
  • $\begingroup$ $t=x^{-1}$ now differentiate it $dt=-x^{-2}dx$ $\endgroup$ – Nebo Alex Jan 11 '17 at 5:23

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