0
$\begingroup$

enter image description here

It is given , that AB=AC=AG. Now,if we draw a circle with centre A and AB as radius then,how should we prove that the circle will also pass through the points C and G?

$\endgroup$
  • 1
    $\begingroup$ Isn't the circle the set of all points at a given distance from its center? $\endgroup$ – AdLibitum Jan 9 '17 at 19:01
2
$\begingroup$

What is the definition of circle in your geometry book?

It is going to be something like, "A circle is the set of all points a given distance from the center."

C,G are the given distance from the circle. They lie on circle A by definition.

$\endgroup$
0
$\begingroup$

The equation of the circle with center$(a, b)$ and radius $r$ is $(x-a)^2+(y-b)^2 = r^2$.

If this equation is satisfied by points A and B, then points A and C also satisfy this since the distances are the same; similarly for A and G.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.