Does there exist such a positive integer $M$ such that, $2\left(M^{2^k}\right)-1$ is prime for all $k= 0, 1, 2, \dotsc$?
I was trying to solve the problem:
Show that there are infinitely many integers which are not sum of a prime and a square.
I ended up showing that there are infinitely many numbers of the form $3k + 1$ which are not sum of a square and a prime. But then I was trying to find a different solution. I assumed that there are finitely many such numbers, and that $M$ is the biggest number which can't be written as a sum of a prime and a square. Then I tried to derive a contradiction by showing that there exists and integer $N$ greater than $M$ such that $N$ is a sum of a square and a prime.