# Straight lines question

In a triangle $ABC$, the bisectors of angles $B$ and $C$ lie on lines $x=y$ and $y=0$. If $A$ is $(1,2)$ then equation of $BC$ is?

The image of $A$ with respect to the angle bisectors of $B$ and $C$ will lie on the line $BC$. This can be deducted from the definition of an angular bisector.
Hence, Image of $(1,2)$ in $x = y$ is $(2,1)$. And Image of $(1,2)$ in $y = 0$ is $(1,-2)$.
$3x-y-5=0$