Is there a composite function with the following inverse function?

Given the following two functions

$$f: \mathbb R \to \mathbb R, \quad f(x)=5-x$$ $$g: [3,\infty[ \to [0,\infty[, \quad g(x)=\sqrt{x-3}$$

determine whether $f \circ g^{-1}$ can be formed. If it can be formed, then find its composite function, and write down the domain and codomain of your composite function.

If it cannot be formed, give a counter-example to support your answer.

I'm not sure whether $g(x)$ is injective and / or surjective.

I guess $g(x)$ is injective because because $g(x)$ can only be non-negative for any $x \ge 3$. And $g(x)$ is surjective because every $g(x)$ has a corresponding element $x$. Therefore $g(x)$ is bijective and has an inverse function.

But I can't figure out $g^{-1}$.

1. Grateful if you can help me confirm whether $g(x)$ is bijective.
2. Can you give me some hints how to fund $g^{-1}$.

Then I can decide whether $f\circ g^{-1}$ can be formed.

Thank you.

You are correct, $g$ is bijective:
• Injectivity: let $\sqrt{x_1-3}=\sqrt{x_2-3} \implies x_1 - 3 = x_2 -3 \implies x_1 = x_2$
• Surjectivity: let $y \in [0, +\infty)$ and let us find $x$ such that $\sqrt{x-3} = y$. Then we get $x = y^2+3 \in [3, +\infty)$
In the last calculation we have also determined that the inverse function is $g^{-1}(x) = x^2+3$.
• Yes, that is also correct, since $f \circ g^{-1}$ domain is $g^{-1}$ domain and its codomain is $f$ codomain. – Harnak Dec 24 '16 at 14:17