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The question is to find the value of $f$ differentiated partially with respect to $x$ (say $f_x$) at $(0,0)$ And the find the value of $f$ differentiated partially with respect to $y$ (say $f_y$) at $(0,0$)

I find $f_x(0,0) =1$ But I am unable to find $f_y(0,0)$

Please helpenter image description here NOTE: Consider $(x,y)\in \mathbb R^2$ in the image.

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  • $\begingroup$ I tried to find fy(0,0) using its formula but I am confused as to take 1 or -1 $\endgroup$ – Abhishek Chandra Dec 24 '16 at 4:36
  • $\begingroup$ If the derivative is different on both sides of the point of interest, what does that tell you about the derivative at the point of interest? $\endgroup$ – Michael McGovern Dec 24 '16 at 4:38
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It is just 0. Recall partial derivative definition:

In mathematics, a partial derivative of a function of several variables is its derivative with respect to one of those variables, with the others held constant

So fy(0, 0) is just going to be:

$$fy(0, 0) = \lim_{\Delta y \to 0} \frac{f(0, \Delta y) - f(0, 0)}{\Delta y}$$

And from the function definition, when $x = 0, f = 0$, so $f(0, \Delta y) - f(0, 0)$ is always zero, which makes the above limit to be zero. And more generally, for this function $fy(0, y) = 0, \forall y$.

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