1) How many eight-card hands can be chosen from exactly 2 suits of an ordinary 52-card deck? (there are 4 suits clubs, diamonds, hearts and spades
I think since there are 26 cards in 2 suits and eight cards from those 26 (order does not matter), thus $C(26,8)/C(52,26)$ ?
2) How many 13-card bridge hands can be chosen from an ordinary 52-card deck that contain six cards of one suit and four and three cards of another two suits? (there are 4 suits clubs, diamonds, hearts and spades
I do not understand 2nd problem.