# Translation of eigenvalue and its bound

First, how to get (6) from (5) ? The (6) implies $$f^{old}=f^{new}\sqrt{g}$$. But I can't get it from $$f'^{~new}=\sqrt{g}f'^{~old}$$. Because $$\sqrt{g}$$ and $$f$$ are functions of $$r$$. Then integrate them , there will be not $$f^{old}=f^{new}\sqrt{g}$$ .

Second, How to get (7) from (4) ?

Thanks for any help.