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A random experiment consists of rolling an unfair, six-sided die. The digit 6 is three times as likely to appear as each of the numbers 2 and 4. Each of the numbers 2 and 4 are twice as likely to appear as each of the numbers 1, 3 and 5 Suppose that the random variable X, is assigned the value of the digit that appears when the die is rolled. What is the expected value of X?

So i got that the added weight is 13 Therefore 6 would have 6/13 chances of getting rolled. I still dont know x, help please

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You get the expected value of X by multiplying each possible number with its probability and adding up:

$1\cdot P(X=1)+2\cdot P(X=2)+...+6\cdot P(X=6)$

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