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Let $$f(x)= \begin{cases} 2x &\text{, x > 3}\\ x^2 &\text{, x $\leq$ 3} \end{cases}$$ and $$g(x)= \begin{cases} x &\text{, x > 2}\\ 5 &\text{, x $<$ 2} \end{cases}$$

I'm asked to find $f(g(x))$, but I don't know how to do it. I handled combinations before, but never of piecewise functions and I don't know where to begin.

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If $x>2$, then $g(x)=x>2$. Hence, $$ \begin{aligned} f(g(x))=f(x)= \begin{cases} 2x&\text{ if }x>3\\ x^{2}&\text{ if }2<x\leq 3 \end{cases} \end{aligned}. $$ If $x<2$, then $g(x)=5>3$. Hence, $$ \begin{aligned} f(g(x))=f(5)=2\cdot 5=10. \end{aligned} $$

In conclusion, we have $$ \begin{aligned} f(g(x))= \begin{cases} 2x&\text{ if }x>3\\ x^{2}&\text{ if }2<x\leq 3\\ 10&\text{ if }x<2 \end{cases} \end{aligned}. $$

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