I've just started to learn about finding terminal points of a unit circle. One thing that I really don't understand is how I would do find the terminal point with a negative angle and with the numbers including square roots. One of my example problems that I can't understand is to choose the point on the terminal side of $-210^\circ$. Wouldn't both the $x$ and $y$ coordinates need to be negative? My options are $(-1,1)$, $(\sqrt{3},-1)$, $(-\sqrt{3},1)$, and $(-1, \sqrt{3})$.

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    $\begingroup$ Do the following: $\sqrt{n}$ for $\sqrt{n}$. I'll fix the formatting up for you, but take a look at the edits to see how it's done in the future. $\endgroup$ – Fine Man Dec 15 '16 at 5:41

"terminal point" isn't standard terminology as far as I know, so I'm just going to take a guess as to what you mean. Let me know if I guessed wrong.

There's not much difference between positive and negative angles. Positive angles just mean you move counter-clockwise from $(1,0)$, and negative angles mean you move clockwise. So the terminal point of $-210^\circ$ should be:

enter image description here

  • $\begingroup$ Nice picture! (+1) $\endgroup$ – b00n heT Dec 15 '16 at 6:06
  • $\begingroup$ MS Paint makes a okay illustrator out of anyone. :) $\endgroup$ – Henry Swanson Dec 15 '16 at 6:19
  • $\begingroup$ That's $-210^\circ$, right? $\endgroup$ – Eric Stucky Dec 15 '16 at 6:45
  • $\begingroup$ @EricStucky Edited. Thanks for the catch! $\endgroup$ – Henry Swanson Dec 15 '16 at 6:58

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