Does Abel or Cesaro summable imply Borel summable for a series? In other words, for a sequence $(a_n)$ and its partial sums $(s_n)$, is it true that: $$ \begin{split} \lim_{n \to \infty}\frac{1}{n}\sum_{k=0}^{n-1} s_k &= A \implies \lim_{t \to \infty}e^{-t}\sum_{n=0}^{\infty}s_n\frac{t^n}{n!} = A\\ \lim_{x \to 1^-}\sum_{n=0}^{\infty}a_nx^n &= A \implies \lim_{t \to \infty}e^{-t}\sum_{n=0}^{\infty}s_n\frac{t^n}{n!} = A \end{split}\;? $$
Is there a proof of this if it is true?
If it isn't, then is there a sequence which is Abel/Cesaro summable but not Borel summable, and is Borel summability consistent with Abel/Cesaro summability?