Epsilon Delta Limit Proofs at and going to infinity. So I understand the concept of epsilon delta limit proofs with linear functions, easy enough, and I am still shaky about doing it with non linear but I am slowly understanding that. I don't quite understand how to tackle them with you have infinity involved. My professor uses M's and N's and I really don't know what these are supposed to represent in terms of the technical definition we are using here.
One of the problems I have to look at is:
$\lim_{x \to \infty} e^x = \infty$
Can anyone give me some other similar examples, not necessarily with $f(x) =e^x$, but any of these proofs that involve infinity, because the normal definition no longer works as written and I don't really know where to begin.
Any resources you can provide me to learn more about this would be greatly appreciated! 
 A: Here, you need to prove that $e^x$ is unbounded.
see http://en.wikipedia.org/wiki/Limit_of_a_function#Limits_involving_infinity
Given any $\epsilon\gt 0, \exists x_0\gt 0$ such that $|f(x)|\gt \epsilon$  $\forall x\gt x_0$.
Choose $\epsilon\gt 0$. Now, we need to find corresponding $x_0$ such that $|e^x|\gt \epsilon $ $\forall x\gt x_0$.
If we take $x_0=\ln\epsilon$, then $|e^x|\gt|e^{x_0}|(=\epsilon)\implies |e^x|\gt \epsilon$ $\forall x\gt \ln\epsilon$, Hence $e^x$ is unbounded and positive and thus $\lim_{x\to\infty}e^x=\infty$
A: If you want to show something like
$$\lim_{x\to\infty} x^2=\infty,$$
then the statement is that, if you go to large enough values of $x$, then the function gets arbitrarily large. More formally, given an arbitrary $M>0$, we can produce an $x_0$ such that, for all $x>x_0$, we will have $x^2>M$. This is what it means to have an infinite limit. In the case of $x^2$, simply take $x_0=\sqrt{M}$.
Similarly, with something like
$$\lim_{x\to 0}\frac{1}{x^2}=\infty,$$
the statement is that if you get close enough to $x=0$, the function gets arbitrarily large. In this case, given $M>0$, we have that $|x|<\frac{1}{\sqrt{M}}$ implies $\frac{1}{x^2}>M$.
