# Exponential Law for based spaces

I realize most people work in "convenient categories" where this is not an issue.

In most topology books there is a proof of the fact that there is a natural homeomorphism of function spaces (with the compact-open topology): $$F(X\times Y,Z)\cong F(X,F(Y,Z))$$ when $X$ is Hausdorff and $Y$ is locally compact Hausdorff. There is also supposed to be a homeomorphism in the based case with the same conditions on $X$ and $Y$: $$F_{\ast}(X\wedge Y,Z)\cong F_{\ast}(X,F_{\ast}(Y,Z))$$involving spaces of based maps and the smash product $\wedge$. This, for instance, is asserted on n-lab. I checked the references listed on this page and many other texts but have not found a proof of this "well-known fact."

It seems pretty clear if $X$ and $Y$ are compact Hausdorff (EDIT: in fact this is Theorem 6.2.38 of Maunder's Algebraic Topology) but can this really be proven in this generality?

Can anyone provide a reference for a proof?

• Can't you get it just from general considerations? The maps in $F_*(X\wedge Y,Z)$ are in one-to-one correspondence with maps in $F(X\times Y,Z)$ that agree on $X\times y_0$ and $x_0\times Y$ and maps them to the base point of $Z$; these maps, under the isomorphism to $F(X,F(Y,Z))$, such an $f$ goes to the map that sends $x$ to $f_x\colon Y\to Z$; since $f$ agrees on all of $X\times{y_0}$, and maps to $z_0$, then $f_x(y_0) = z_0$, so the image is in $F_*(Y,Z)$, and $f_{x_0}$ maps tot he constant function $Y\mapsto z_0$, which is the basepoint of $F_*(Y,Z)$. Isomorphism should follow from lifts. – Arturo Magidin Feb 4 '11 at 21:46
• Showing the desired isomorphism is a homeomorphism should require you make use of compact sets in the quotient space $X\wedge Y$. This is non-obvious to me. Are you sure the space $F_{\ast}(X\wedge Y,Z)$ is homeomorphic to the relative mapping space $F((X\times Y,X\vee Y),(Z,z_0))$? – J.K.T. Feb 5 '11 at 0:07

• I checked this out. Prop. 6.2.37 and 6.2.38 say: $F_{\ast}(X\wedge Y,Z)\rightarrow F_{\ast}(X,F_{\ast}(Y,Z))$ is 1-1, continuous if $X$ is Hausdorff, onto if $Y$ is locally compact Hausdorff, and a homeomorphism if $X$ and $Y$ are compact Hausdorff. So you have a continuous bijection as Arturo points out, but I am not yet convinced. – J.K.T. Feb 5 '11 at 19:36
• I understood the question in the sense that the OP wants a homeomorphism $F_{\ast}(X\wedge Y,Z)\cong F_{\ast}(X,F_{\ast}(Y,Z))$ for $X$ Hausdorff and $Y$ locally compact Hausdorff (and no idea what hypotheses on $Z$, if any) says that he found a reference for the compact case but has no idea about the aforementioned one. It seems to me that the problem is that $X$ is not necessarily compactly generated. – t.b. Aug 9 '11 at 11:48
• @J.T.,@Theo Ah, it's true, perhaps; sorry. If that's the case, I'll delete my answer. – Grigory M Aug 9 '11 at 11:53