# Midpoint for a triangle area question?

In triangle $ABC$ the three midpoints of the sides are $P, Q, R$. The midpoints of sides in triangle $PQR$ are $K, L, M$. What is the area of triangle $ABC$ if the area of triangle $KLM$ is $5$?

I started by drawing a picture with all the information. This gave me a a big triangle split into $4$ smaller triangles with the one in the middle being split again into $4$ pieces. If that one little piece has area $5$, do you get $5*2^2$ as area for the medium triangle, so also do you get $5*4^2=80$ for the whole thing? Is there a way to prove that the areas of the split triangles are the same?

By similarity, its base and height are both half of the original triangle. So $area =1/2*base*height$ is $1/4$ original. (As both base and height are halved)
So area of $PQR=4*$Area of $KLM=20$
Area of $ABC=4*$area of $PQR=80$
You can say that the two triangles $ABC$ and $KLM$ are similar by the intercept theorem with similarity ratio $4$, so the ratio between the two areas is $16$ and $ABC(area)=80$.