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There is a simple question for identity:

$\log_{ab}X = \frac{\log(a)X \times \log(b)X}{\log(a)X + \log(b)X}$

To proof, I goes for $ab$ base for right, but seems Im wrong.

Can anyone help?

Thank you!

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  • $\begingroup$ Did you mean $\frac{\log_{a}X\times\log_{b}X}{\log_{a}X+\log_{b}X}$? $\endgroup$ – barak manos Dec 4 '16 at 16:44
  • $\begingroup$ yes! Solved! Thanks! $\endgroup$ – Garry Boch Dec 4 '16 at 17:12
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Hint:

$$\log_r s=\frac1{\log_s r}$$

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