# Is it possible to create a system of two equations with 3 variables and only one solution?

I know that a system of equations with 3 variables usually has to contain at least 3 equations, but are there any special cases where 2 equations with 3 variables have just one solution? I've researched a bit, and found 2 equations with 3 variables with finite solution sets, but are there any that have exactly one solution? The equations could be linear or quadratic or cubic or sinusoidal or anything... but does such a case exist?

Also, is it possible to find such a case if we know any 2 variables? Like, for example, $a + b + c = w$ and $b + c = d$, given b and d. (of course, this example has more than 1 solution, but are there any like this that have just 1 solution)

Thanks for any help!

Edit:

To clarify, I'm looking for the general form of such an equation. To be more specific, are there any systems of 2 equations, with 3 variables, that only have 1 solution, but which can be modified to have any 1 solution I desire.

Yes there is. $x^2+y^2=0$ and $z=0$.
Edit: $(x-a)^2+(y-b)^2=0$ and $z-c=0$
• This gives an unique solution in $\mathbb{R}^3$. Is there any way a system could return an unique solution in $\mathbb{C}^3$? – GLay Dec 2 '16 at 4:44
• @GLay In $\mathbb{C}^3$ it can't be polynomials, since $\mathbb{C}$ is algebraically closed. But you could take any function $f : \mathbb{C} \to \mathbb{R}$ with the property that $f(z)=0 \iff z=0$ then the equation $f^2(x-a)+f^2(y-b)+f^2(z-c)=0$ would have the unique solution $x=a,y=b,z=c$. For example, $f(w) = |w|$. – dxiv Dec 2 '16 at 4:57