example of a convergent series whose alternating series diverges? Basically my question is the title:
If have some series $\sum a_n$ which converges and is nonnegative for all its terms, im looking for an example for $a_n$ such that its alternating series $\sum (-1)^n a_n$ is divergent. 
I was doing a problem relating to convergence of a power series and looked at the solution and it evoked the alternating series test, which required (1) a decreasing (2) nonnegative sequence (3) whose limit is zero in order for its alternating series of that sequence to converge. The solution did not check if the sequence was decreasing so im a little puzzled and thats why im here.
For anyone interested in the solution, its problem 2(a) at this link:
http://www.northeastern.edu/suciu/MATH3150/MATH3150-fa15-hmw6-solutions.pdf
 A: Notice that
$$|a+b|\le|a|+|b|$$
This is known as triangle rule, and it can be easily seen that it implies
$$|a_1+a_2+a_3+\dots+a_n|\le|a_1|+|a_2|+|a_3|+\dots+|a_n|$$
Putting this into context, it is readily seen that
$$0\le\left|\sum_{n=1}^\infty(-1)^{n+1}a_n\right|\le\sum_{n=1}^\infty\left|(-1)^{n+1}a_n\right|=\sum_{n=1}^\infty a_n=S<\infty$$
So clearly the sum is bounded.
Now, we are left with two cases: the summation bounces or oscillates between at least two values, and thus, it shall never converge but remain bounded as above. Or it will converge.  (The third case for any series is to diverge to $\pm\infty$, but we have already shown this not possible)
The term test tells us that
$$\lim_{n\to\infty}a_n=0$$
As should be quite obvious.  It then goes to show that our sum cannot oscillate, leaving the only remaining possibility being convergence.
A: If a series is absolutely convergent, then it is convergent. The proof can be found here: http://pirate.shu.edu/~wachsmut/ira/numser/proofs/absconv.html
