# !How to properly input this query in wolfram alpha? [duplicate]

The thing I want to input:

$$\frac{1}{n+1} + \frac{1}{n+2} + ... + \frac{1}{2n} > \frac{13}{24}, n>1$$

The best I managed so far:

https://www.wolframalpha.com/input/?i=prove+by+induction+sum_%7Bi%3D1%7D%5En+1%2F(n%2Bi)+%3E+13%2F24,+n%3E1

But it says it's not true. I can do the first step of the proof and it's true (for n=2).

Wolfram Alpha input and result

my question is not a duplicate, as it's about wolfram alpha not interpreting this correctly.

## marked as duplicate by Namaste, E. Joseph, Henrik, user186473, Daniel W. FarlowNov 26 '16 at 20:37

Wolfram Alpha gives bizarre answers... Set $S_n = \sum_{i=1}^{n} \frac{1}{n+i}$ We have $S_{n+1}- S_n = + \frac{1}{2n+1} - \frac{1}{2(n+1)} \geq 0$. Therefore $(S_n)$ is increasing. $S_2 = \frac{7}{12}>\frac{13}{24}$. Hence the result ...