0
$\begingroup$

It's repetitive and I'm just confused on what to do; I know we have to find a LCD but the fraction-over-fraction-over-fraction is throwing me off.

$$x + \frac{1}{x+\frac{1}{x+\frac{1}{x}}}$$

$\endgroup$
  • $\begingroup$ What's the deal with "$1(x)$"??? Why not just use $x$? $\endgroup$ – barak manos Nov 23 '16 at 5:47
  • $\begingroup$ Whoops, I forgot a couple of parenthesis, I fixed them now. Hopefully it makes sense! $\endgroup$ – Sweetcharge Nov 23 '16 at 5:52
2
$\begingroup$

\begin{align} x+\frac{1}{x+\frac{1}{x+\frac{1}{x}}} &= x+\frac{1}{x+\frac{1}{\frac{x^2+1}{x}}}\\&= x+\frac{1}{x+\frac{x}{x^2+1}}\\&= x+\frac{1}{\frac{x^3+2x}{x^2+1}}\\&= x+\frac{x^2+1}{x^3+2x}\\&= \frac{x^4+3x^2+1}{x^3+2x} \end{align}

$\endgroup$
  • $\begingroup$ Wow, thank you! My work was just messy I guess and I ended up confusing myself. Thank you so much!! $\endgroup$ – Sweetcharge Nov 23 '16 at 6:03
  • $\begingroup$ @Sweetcharge: You're welcome. Feel free to accept the answer by clicking on the V next to it :) $\endgroup$ – barak manos Nov 23 '16 at 6:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.