# Prove $\int_{-b}^{\infty}\log^{\nu}(t+b)e^{-t}e^{-e^{-t}}dt\xrightarrow{b\rightarrow\infty} \log^{\nu}(b)$

How to prove $$\int_{-b}^{\infty}\log^{\nu}(t+b)e^{-t}e^{-e^{-t}}dt\xrightarrow{b\rightarrow\infty} \log^{\nu}(b),$$ where $\nu$ is any real or complex number. I have validated this asymptotic in MATLAB with numerical method.

Note that in our previous post (please refer to How to approximate the integral $\int_{-b}^{\infty}\log(t+b)e^{-t}e^{-e^{-t}}dt$), the special case $\nu=1$ was proved by @tired, however, this method only applies to the case $\nu=1$ rather than the general value of $\nu$. There should be a general method to prove it.

• how do you define $\log^{\nu}(z)$ on the interval $z \in \{0,1\}$? Nov 14 '16 at 18:53
• sorry, I didn't get your concerning... Nov 14 '16 at 21:11
• for $t+b<1$ the logarithm gets negative. Now we have to answer the question how to take the non-integer exponent of this quantity (you may recall the for example the square root is a multivalued function in the complex plane) Nov 14 '16 at 21:14
• Take the definition in MATLAB: For negative and complex numbers z = u + iw, the complex square root sqrt(z) returns sqrt(r)*(cos(phi/2) + 1isin(phi/2)) where r = abs(z) is the radius and phi = angle(z) is the phase angle on the closed interval -pi <= phi <= pi. Nov 14 '16 at 21:31
• Suppose that $\int_{-b}^{\infty}\log^{\nu}(t+b)e^{-t}e^{-e^{-t}}dt\xrightarrow{b\rightarrow\infty} \log^{\nu}(b)$ holds, if we can prove $\int_{-b}^{\infty}\log^{\nu+\delta}(t+b)e^{-t}e^{-e^{-t}}dt\xrightarrow{b\rightarrow\infty} \log^{\nu+\delta}(b)$, then it accomplish the proof. Is it simpler to prove in such way? Nov 15 '16 at 10:47