I am trying to solve this question:
Let X have the pdf:
$f(x) = 6(x-x^2)$ $if$ $0\le x \le1$
Show that Y ~ U(0,1)
I am having trouble finding the pdf of Y since I don't know how to find $g^-1(y)$ when Y is defined this way. Can anyone help me get on the right track?