# Computing a tricky limit

$$\lim_{n \to \infty} \frac{1^m + 2^m + 3^m + ... + (2n-1)^m }{n^{m+1}}$$

I am kind of stuck since I cannot make it look into a form that would involve the integral of certain function. I know somehow it would be easy if we can compare this limit to a riemman sum. Any ideas?

• Nov 2 '16 at 6:42

• The $\approx$ should be $\lim_{n \rightarrow \infty}$