How to solve: $y'+\frac yt=3\cos2t$, $t>0$ (using variation of parameters)? I know the solution using the integrating factor method, which is $\frac ct+\frac{3\cos2t}{4t}+\frac{3\sin2t}2$.

Thanks in advance.

  • $\begingroup$ I've just edited. Thank you. $\endgroup$ – Amália Oct 26 '16 at 14:50

A hint:

The given differential equation can be written as $$(t\>y)'=3t\cos(2t)\qquad(t>0)\ .$$


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