-2
$\begingroup$

Two cards were drawn, without replacement, from a pack of 52 cards. What is the probability that they are both Kings or both Queens ?

$\endgroup$

closed as off-topic by Did, Davide Giraudo, Jack's wasted life, iadvd, user223391 Oct 29 '16 at 5:37

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Did, Davide Giraudo, Jack's wasted life, iadvd, Community
If this question can be reworded to fit the rules in the help center, please edit the question.

  • 1
    $\begingroup$ What is the probability that the first card is a king ? $\endgroup$ – callculus Oct 25 '16 at 16:25
1
$\begingroup$

Probability that both are kings (or) both are queen's = Both are kings + Both are Queen's

Probability that first drawn Card is a king $= \frac{4}{52}$ and card is not replaced then, probability of second card being king $= \frac{3}{51}$

P(both are kings) $=\frac{4}{52}*\frac{3}{51}$,Similarly P(both are queens) $ = \frac{4}{52}*\frac{3}{51}$

So required probability $= \frac{4}{52}*\frac{3}{51} +\frac{4}{52}*\frac{3}{51} = 2*\frac{4}{52}*\frac{3}{51} = \frac{2}{221}$

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.