Consider:
\begin{align}
\int_{0}^{\pi} \sqrt{\sin\theta} \, d\theta &= \int_{0}^{\pi/2} \sqrt{\sin\theta} \, d\theta + \int_{\pi/2}^{\pi} \sqrt{\sin\theta} \, d\theta \\
&= \int_{0}^{\pi/2} \sqrt{\sin\theta} \, d\theta + \int_{0}^{\pi/2} \sqrt{\sin(\theta + \pi/2)} \, d\theta \\
&= \int_{0}^{\pi/2} \sqrt{\sin\theta} \, d\theta + \int_{0}^{\pi/2} \sqrt{\cos\theta} \, d\theta \\
&= \frac{1}{2} \, \left( B\left(\frac{3}{4}, \frac{1}{2} \right) + B\left( \frac{1}{2} , \frac{3}{4}\right) \right) \\
&= B\left(\frac{3}{4}, \frac{1}{2} \right) = \frac{4\pi}{s},
\end{align}
where $s$ is the lemniscate constant.