Pronouncing $A\triangle B$ How would one pronounce an expression involving a set symmetric difference, such as $A\triangle B$?  Would that be read "A symmetric difference B?"  Or perhaps something like "A xor B?"
This came up when I was teaching a course involving elementary set theory and I was having trouble reading statements like $A \cup (B \triangle C)$ out loud.
Thanks!
 A: Just because something is written in a certain order doesn't mean it has to be pronounced that way. For instance, when you say '£5' (or '$5' if you're that way inclined), you'd say 'five pounds' (or 'five dollars'), rather than 'pounds five' (or 'dollars five').
The same applies here. $A \triangle B$ denotes 'the symmetric difference of $A$ and $B$', and that is a perfectly good way of pronouncing it.

Edit (in response to the latest edit to the question): Likewise $A \cup (B \triangle C)$ could be pronounced 'the union of $A$ [with/and] the symmetric difference of $B$ and $C$', or perhaps '$A$ union the symmetric difference of $A$ and $B$'.
A: I would say "the symmetric difference of $A$ and $B$."  In certain contexts "$A$ xor $B$" would work too.
A: As a student, if I am writing what the lecture reads I would prefer to hear $A$ symmetric difference $B$ since it would save me the time in having to 'translate it' when I write it in my notebook (when I tooked set theory it was said in this way)
