I have the question "Using the equation and information below, derive the units for the permittivity of free space , $\epsilon_{_0}$.
$V = \dfrac 1 {4 \pi \epsilon_{_0}} ~ \dfrac Q r$
$V$ is voltage in volts, $Q$ is charge in coulombs, $r$ is distance in metres, $4$ and $\pi$ are numbers and have no units."
From this information do I need to rearrange the formula to make e0 the subject and then workout the si units of each value?
When I checked the solutions the answer to this is $Q/Vm$ or $QV^{-1}m^{-1}$.