Let $\gamma\colon [0,1] \to \mathbb R^2$ (continuous) be a simple closed plane curve and $\,\mathcal C$ its image. Let $x,y$ be some functions such that $\gamma(t)=(x(t),y(t))$. $\gamma$ is said differentiable if $x,y$ are differentiable, $\gamma'(0)=\gamma'(1)$ and $\gamma'(t)$ is never the zero vector.
$\gamma$ is said strictly convex if for any two points in the interior of $\,\mathcal C$, the line segment that joins them stays entirely inside the interior of $\,\mathcal C$ and for any two points in $\,\mathcal C$, the line segment that joins them is not included in $\,\mathcal C$.
Question 1. Let's assume $\gamma$ is differentiable and strictly convex. Is it true that for any line $r$ in the plane there are exactly two lines tangent to $\,\mathcal C$ and parallel to $r$?
Two points $A,B \in \mathcal C$ are opposite if the tangent lines to $\,\mathcal C$ at $A$ and at $B$ are parallel. Two opposite points are minimally diametrical if their (Euclidean) distance is the minimum among the distances of opposites points.
Question 2. Is it true that there are at least two pairs of minimally diametrical points in $\,\mathcal C$? If $A,B$ are minimally diametrical, is the line through $A,B$ perpendicular to the tangent lines at $A,B$?
I was wondering whether I can answer these questions using the extreme value theorem, as it seems one of those problems when there's a continuous function on a closed interval... But I can't see how to apply it in this case.
Answer to Edu.
Red points are on parallel lines not perpendicular to the line through them. If we force the red points to be opposite, then (I think) we can find some points (black) near the red points with parallel tangent lines and smaller distance. This would imply that the red points are not minimally diametrical.