# Cauchy-like functional equation $f(x+g(x)y)=f(x)+f(g(0)y)-f(0)$

I have the functional equation $$f(x+g(x)y)=f(x)+f(g(0)y)-f(0)$$ where

• $f$ is monotone increasing and continuous
• $g$ is continuous and positive
• The domain of both functions is a closed interval that includes 0.

The obvious solutions are:

• $g$ constant and $f$ linear
• $f$ constant and $g$ arbitrary.

There is also another solution:

• $g(x)=x+1$, and $f(x)=ln(x+1)$.

The question is whether there are other solutions? In particular, I am interested in the question: if $g(0)\neq 1$ is $f$ necessarily linear?

Thanks.

Let $g(0)=0$ for this example.
$$f(x+g(x)y)=f(x)$$
Since $f(x)$ is injective, this can only hold for $0=g(x)y$, except we have the problem that $y$ can be anything. Thus the only solution for this case is $g(x)=0$, which gives $f(x)$ be any monotone increasing continuous function defined at $x=0$.
We may then choose $f(x)$ to be non-linear, a contradiction to your claim.
• You are totally right. I forgot to mention that $g$ are $h$ are both positive. I will fix in the question. Thanks. – mike Oct 12 '16 at 17:46
• Sorry, $h$ is not present in this problem. $g$ is positive. – mike Oct 12 '16 at 17:48