I want to calculate the Fourier transform of the Fejer kernel $\mathcal{F}_N$ on the real line, which is given by $$\mathcal{F}_N(x)= \begin{cases} N\Big(\frac{\sin \pi xN}{\pi xN}\Big)^2, & \text{if $x\neq 0$} \\[2ex] N, & \text{if $x=0$} \end{cases} $$

I want to find $\hat{\mathcal{F}_N} (n)=N\int\Big(\frac{\sin \pi xN}{\pi xN}\Big)^2 e^{-2\pi ixn}dx$, but so far I can't think of any transformations to compute this integral. I would greatly appreciate any help.

  • $\begingroup$ You can use the convolution theorem $$\int_{-\infty}^{\infty} dx \ f(x) g^*(x) e^{i k x} = \frac1{2 \pi} \int_{-\infty}^{\infty} dk' \ F(k') G^*(k-k') $$ where $f$ and $F$ are Fourier transform pairs, as are $g$ and $G$. In this case both $f$ and $g$ are $\sin{\pi N x}/{\pi N x}$ so that $F$ and $G$ are $\pi N \operatorname{rect}{\pi N k}$. $\endgroup$ – Ron Gordon Oct 8 '16 at 11:34
  • $\begingroup$ @RonGordon I'm not familiar with the notation rect here can you explain what it means? $\endgroup$ – takecare Oct 8 '16 at 11:39
  • $\begingroup$ It is a rectangular pulse of width $1/(\pi N)$ centered at the origin. $\endgroup$ – Ron Gordon Oct 8 '16 at 11:40
  • $\begingroup$ Is it possible to calculate the Fourier transform of $\sin x/x$ via straightforward integration or do I need to use a different trick? $\endgroup$ – takecare Oct 8 '16 at 11:41
  • $\begingroup$ Oh yes, it is possible. I would do it via contour integration in the complex plane. $\endgroup$ – Ron Gordon Oct 8 '16 at 11:41

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.