# How much more time will it take to finish the filling the pool?

The question is:

An empty pool being filled with water at a constant rate takes 8 hours to fill to \frac{3}{5} of its capacity.How much more time will it take to finish the filling the pool? (Ans 5 hr 20min)

Now here is how I am solving it:

The entire time required to fill the pool would be $\frac{40}{3}$ hours or $13$ hours and $1$ min

So how much more time would be $(13-8)$ hours will be $5$ hours and $1$ min.Why am i getting the wrong answer. I would appreciate it if someone could tell me where I am going wrong

• $40/3$ hours is 13 hours and $\bf 20$ minutes ($13$ hours and $1/3$ hours). Sep 14, 2012 at 0:51
• @DavidMitra could you please tell me how you got 13 hours and 20 min ? I get a remainder of 1 or 13$\frac{1}{3}$$when I divide 40 by 3 ? Sep 14, 2012 at 0:56 • Yes,$40/3=13+1/3$. So it's$13$and$1/3$hours.$1/3$of an hour is$20$minutes. Sep 14, 2012 at 1:00 • Oh okay. (1/3) of an hour. Now I get it thanks for clearing that up Sep 14, 2012 at 1:01 ## 2 Answers Your basic reasoning is correct; however, you made two errors in converting$40/3$hours into hours/minutes. First,$40/3$is not$13.1$(as you seem to imply), it's$13.\overline3$or$13\,{1\over3}$. Second, the decimal part of this is not minutes, it's still hours. So you have$13$and$1/3$hours.$1/3$of an hour is$20$minutes. So,$40/3$hours is$13$hours and$20$minutes. How did you reason: "the entire time required to fill the pool would be 40/3 hours or 13 hours and 1 min."? Hint: 40/3 seems right. • Because if$\frac{3}{5}$requires$8$hours then$1$would require$\frac{5\times8}{3}\$ ? Am I wrong ? Sep 14, 2012 at 0:54
• Yea, that part is right, what I meant is what about the 13 hours and 1 min? Sep 14, 2012 at 1:03
• That is where i was wrong. I thought the remainder represented a minute. Sep 14, 2012 at 1:04
• Actually is 1/3 of an hour Sep 14, 2012 at 1:05