# Probablity_basics_Straight Flush

What is the probability that a ﬁve-card poker hand contains a straight ﬂush, that is, ﬁve cards of the same suit of consecutive kinds?

My Approach /Attempt -:

Number of Straight Flush Possible=$\binom{10}{1}*\binom{4}{1}*\binom{13}{5}$

$\binom{10}{1} \Rightarrow$ a straight can start with any of the $\left(A,2,3,4,5,6,7,8,9 ,10\right)$

$\binom{4}{1} \Rightarrow$ pick one of the 4 suits

$\binom{13}{5} \Rightarrow$ select 5 cards from the selected suit containing 13 cards.

P(Straight Flush)=$\left ( \binom{10}{1}*\binom{4}{1}*\binom{13}{5} \right )/\binom{52}{5}$

Am i correct?

• Assume only low Straight allowed,i mean only (A,2,3,4,5,6,7,8,9,10) allowed ,No (10,9,8,7,6,5,4,3,2,A) allowed neither (10,J,Q,K,A) – virat Sep 28 '16 at 6:32
• Please choose informative and precise titles instead of vague ones. I showed you how to do so in your previous question. – Did Sep 28 '16 at 13:25