2
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$$7y^{2a+b}-5y^{a+b}+3y^{a+2b}$$

I don't really kow how to start...I guess a $y$ could be factored out but that's completely useless.

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2
$\begingroup$

$$ 7y^{2a+b}-5y^{a+b}+3y^{a+2b}=y^{a+b}(7y^a-5+3y^b) $$

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  • $\begingroup$ Wait...that's it? $\endgroup$ – thunderbolt Sep 22 '16 at 4:29
  • $\begingroup$ I think so! It is a factorisation isn't it? $\endgroup$ – KonKan Sep 22 '16 at 4:30
  • $\begingroup$ Yes, thanks! Surprised it turned out to be so simple $\endgroup$ – thunderbolt Sep 22 '16 at 4:30

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