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I have the question "Find the coordinates of the mid-point of the line segment joining each pair of points (-5/4, 2) and (-1, -3/5) " I wanted to know the different ways to solve this and could you please show your working so that I understand how to tackle these types of questions better thanks.

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closed as off-topic by JonMark Perry, 5xum, heropup, Pierre-Guy Plamondon, Daniel W. Farlow Sep 14 '16 at 23:07

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  • $\begingroup$ please show us your working first !!! Don't expect us to solve your homework problems for you. $\endgroup$ – Dark_Knight Sep 14 '16 at 11:30
  • $\begingroup$ ((-5/4 + -1) / 2 , (3 + -3/5) / 2) $\endgroup$ – Dan Khan Sep 14 '16 at 11:32
  • $\begingroup$ i'm just not sure if this is the right way to solve the question. $\endgroup$ – Dan Khan Sep 14 '16 at 11:33
  • $\begingroup$ Dan-- In your comment the 3 should be a 2 in second coordinate. $\endgroup$ – coffeemath Sep 14 '16 at 11:35
  • $\begingroup$ Dan--Now in the edited version there aren't two points anymore. $\endgroup$ – coffeemath Sep 14 '16 at 11:38
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Well, there is the aptly-named midpoint formula, written as $$\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) $$ While this may look complicated, it really just means taking the mean (average) of the $x$ coordinates and the $y$ coordinates.

To do the calculation, you'd do $$\frac{-\frac{5}{4} + -1}{2}$$ for the x-coordinate and $$\frac{2+-\frac{3}{5}}{2}$$ for the y-coordinate. This comes to $$-\frac{9}{4}*\frac{1}{2}$$ (remember multiplying by $\frac{1}{2}$ is the same as dividing by 2) which then gives $$-\frac{9}{8}$$ for the x-coordinate. You can do the y-coordinate.

Hope this helps!

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  • $\begingroup$ Could i leave the answer as (-1.125, 0.72) rather than a fraction ? and is this final answer correct ? $\endgroup$ – Dan Khan Sep 14 '16 at 11:45
  • $\begingroup$ Yes, you can leave it as a decimal. However, your y-coordinate doesn't seem to be quite right, try it again. $\endgroup$ – heather Sep 14 '16 at 11:47
  • $\begingroup$ Is 0.7 correct ? $\endgroup$ – Dan Khan Sep 14 '16 at 11:48
  • $\begingroup$ @DanKhan, yes, I believe so. $\endgroup$ – heather Sep 14 '16 at 11:49
  • $\begingroup$ How do i do that ? $\endgroup$ – Dan Khan Sep 14 '16 at 11:50

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