I have two vectors with a known direction and unknown magnitudes.
$V_1 = A(m) @ 20°$, $V_2 = B(m) @ 300°$ and $V_3 = 166m @ 140°$ such that $V_1 + V_2 + V_3 = 0$
I'll tell you what I do know. From my point of view $V_3$ is the equilibrant vector being that $V_1$ and $V_2$ add up to be $0$. What I don't know/remember is how to solve for two unknowns. I know there are up to two methods for solving for two unknowns (substitution, and elimination). Also, I can break the vectors down into their individual $x$ and $y$ components.
$V_1 = (A \cos(20°),A \sin(20°))$
$V_2 = (B \cos(60°), -B \sin(60°))$
$V_3 = (-166\cos (40°), 166\sin(40°))$
However, I am unsure of where to go from here. Thanks!