divisibility homework question I'm stuck on this problem for my math homework and could really use some help.

Definition A: Let $a$ and $b$ be integers. We say that $a$ is divisible by $b$ provided there is an integer $c$ such that $bc = a$.
Definition B: Let $a$ and $b$ be integers. We say that $a$ is divisible by $b$ provided $a/b$ is an integer.

The question asks to find integers $a$ and $b$ that are divisible according to one definition, but are not divisible according to the other.
Any guidance would be really appreciated.
 A: Thanks to @aduh, I have solved the question: 
Let $a=  b=0$. In Definition A, $a$ is divisibile by $b$ since $0c = 0$, where $c=0$. In definition B, $a/b = 0/0$ is undefined.
A: In the following I'll use the abbreviation "A-divisible" (resp. "B-divisible") for "divisible according to definition A (resp. B)".


*

*If $a$ is B-divisible by $b$, then $a$ is A-divisible by $b$.
Proof: If $a$ is B-divisible by $b$, it means that $a/b$ is an integer. Therefore $c=a/b$ is an integer such that $bc=a$, thus such an integer exists, and thus $a$ is A-divisible by $b$.

*If $a$ is A-divisible by $b$, then exactly one of the following are true:


*

*$a$ is B-divisible by $b$.

*$a=b=0$.


Proof: If $a$ is A-divisible by $b$, then there exists an integer $c$ such that $bc=a$. Now either $b=0$ or $b\ne0$.
If $b\ne 0$, then both sides of the equation can by divided by $b$ to get the equivalent equation $c=a/b$. Since $c$ is an integer, so is $a/b$, and thus $a$ is B-divisible by $b$.
If $b=0$ then for any integer $c$, $bc=0$, and therefore the equation $bc=a$ can only be fulfilled if also $a=0$; on the other hand, if $a=b=0$, then any integer $c$ causes the equation $bc=a$ to be true.
Obviously exactly one of $b=0$ or $b\ne 0$ is true.
Therefore there exists exactly one pair of integers $a$ and $b$ such that $a$ is divisible by $b$ only according to one of the definitions, and that is $a=b=0$. $0$ is A-divisible by $0$, but $0$ is not $b$-divisible by $0$.
