$\lim_{x \rightarrow 0}\left(\frac{1}{\sin^2(x)} -\frac{1}{x^2}\right)$ and the problem of $\infty-\infty$ [duplicate]

I'm trying to calculate

$$\lim_{x \rightarrow 0}\left(\frac{1}{\sin^2(x)} -\frac{1}{x^2}\right)$$

but I'm having the problem of getting

$$\infty - \infty$$

which I read to be indeterminate.

I cannot figure out how could I manipulate the above to get rid of the indeterminacy.