A particle is projected with an initial speed of $35 m/s$ from the base of a plane inclined at an angle $\varphi$ to the horizontal where $\varphi=\arctan(3/4)$. If the projectile is initially angled at $\theta$ to the horizontal, where $\tan \theta =5/2$ , ﬁnd how far along the plane the projectile lands, and the time of ﬂight
ANS: 75.431 m, approx. 4.64 s
I can get the position vector for the particle but that is as far as i can get on my own. I don't know how to solve for the point of collision with the inclined plane and everything i try doesn't match the answer in the book.