$$x_i'=\sum_{k=1}^3 c_{i,k}x_k + \overset{\circ}{x_i}'$$
The new coordinate equals a scale and skew transform of the old coordinate plus a shift vector; which is the new coordinates of the origin (zero vector) after the transformation.
$$\because\quad\begin{pmatrix}x_1'\\x_2'\\x_3'\end{pmatrix} = \begin{pmatrix}c_{1,1}&c_{1,2}&c_{1,3}\\c_{2,1}&c_{2,2}&c_{2,3}\\c_{3,1}&c_{3,2}&c_{3,3}\end{pmatrix}\begin{pmatrix}x_1\\x_2\\x_3\end{pmatrix}+\begin{pmatrix}\overset{\circ}{x_1}'\\\overset{\circ}{x_2}'\\\overset{\circ}{x_3}'\end{pmatrix}$$
$$\therefore\quad\begin{pmatrix}\overset{\circ}{x_1}'\\\overset{\circ}{x_2}'\\\overset{\circ}{x_3}'\end{pmatrix} = \begin{pmatrix}c_{1,1}&c_{1,2}&c_{1,3}\\c_{2,1}&c_{2,2}&c_{2,3}\\c_{3,1}&c_{3,2}&c_{3,3}\end{pmatrix}\begin{pmatrix}0\\0\\0\end{pmatrix}+\begin{pmatrix}\overset{\circ}{x_1}'\\\overset{\circ}{x_2}'\\\overset{\circ}{x_3}'\end{pmatrix}$$
That is all.