Okay so I have to find the area bounded by $y= x^2-3x+2,x=1,x=2$ and $y=0$
I sketched the graphs and tried to solved it like this
Okay so I took the integral for the quadratic from $x=1$ to $x=2$ which should give me the area of the curved part (which is the required answer) plus all the area above x axis and in between $x=1$ to $x=2$. I know I need to subtract this second area but don't know how. Any help would be appreciated.