My suspicion is that I need to find the conjugate to get this in a more factorable form. From there, I think I can plug in $16$ to find the limit. The only issue is that I'm not quite sure how to factor this. This is my first Calc class and I've never factored anything quite like this before. I found the following format for factoring this sort of problem:
$$(a-b)\left(a^3+a^2b+ab^2+b^3\right) = a^4-b^4$$
But I'm pretty confused in terms of how to apply it (do I apply it to the numerator and then try to get the denominator into a similar form to cancel stuff out?). Does $a = x^\frac14$, and $b = 2$? I feel like the toughest part of this problem is the factoring, not the Calculus.