0
$\begingroup$

I've been having some trouble trying to evaluate $\int_0^\pi (\frac{\pi}{2}-x)\tan x\cdot\frac{dx}{x}$

Standard Integration by Parts failed, because if one splits the integral, the integrand ends up being $\frac{\pi}{2x}\tan x - \tan x$. But because the integral has bounds from 0 to pi, one cannot integrate over pi/2 due to convergence issues. Thus, I am not sure how to go about this integral from here. Any help would be appreciated.

$\endgroup$
  • $\begingroup$ Did you plot the function $(\frac{\pi}{2}-x)\frac{\tan x}{x}$ for $0 \leq x \leq \pi$ ? $\endgroup$ – Claude Leibovici Aug 23 '16 at 10:12
  • $\begingroup$ Yes, but why would that help? $\endgroup$ – Why Do You Care Aug 23 '16 at 10:21

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.