1) A and B are playing a game where they each write their name on a card. A goes first and chooses one of the two cards with equal probability. If A chooses her own card then she wins. If she chooses B’s card, then it is B’s turn to play. He chooses one of the two cards randomly with equal probability, and he wins if gets his own card. Otherwise, the turn passes back to A and she tries again. This pattern continues until one or the other has won. Calculate the probability that A will win this game. (it is not 1/2.)
I'm assuming the way to do this is geometric distribution, but I'm still a but confused on this. I was trying to use sigma notation to denote how to calculate it, but I don't know how to go about this. I'm getting 1/2 which obviously isn't the answer.
2) C walks up and wants to join the game so she adds a card with her name into the pile. Now, if A draws B’s card then he goes next and if she draws C’s card then C goes next. At each turn, the person drawing a card will win if they draw their own card, and otherwise the turn will pass to whoever is named on the card. Every card is drawn independently with all three cards having equal probability. They continue to take turns until somebody wins. Calculate the probability of A winning, the probability of B winning, and the probability of C winning.
Also assuming this is the same approach as the last problem, but instead of using 1/2, we use 1/3.