The question was:
From the letters in MAGOOSH, we are going to make three-letter "words." Any set of three letters counts as a word, and different arrangements of the same three letters (such as "MAG" and "AGM") count as different words. How many different three-letter words can be made from the seven letters in MAGOOSH?
From my permutation understanding, ans should be: 7P3/2! = 105 But the answer is: 6P3+(3*5)=135 (I understand how it happens!)
But my question is, why indistinguishable object's permutation formula = nPr/K! could not be applied here.(Such as MOM = 3P3/2!=3!/2!=3)
So, I am not sure why "7P3/2!" - is not a valid answer as there is 2 "O"s. What am I missing here? Any explanations?