So I am trying to analytically continue the formula for the partial sums of the Riemann zeta function by using the fact that, if $\zeta_{k}$ represents the $k^{\text{th}}$ partial sum of the zeta function then:

$$\zeta_{k} =\sum_{n=1}^{k} n^{-s}$$

and an alternative definition in the form of,

$$\zeta_{k}(s) = \zeta(s) - \zeta(s,k+1)$$

Both the zeta function and Hurwitz zeta function and the zeta function can be expressed in terms of Abel-Plana formulae:

$$ \begin{align} \zeta \left(s\right) &= \frac{2^{s-1}}{s-1} -2^s\int_{\mathbb{R}^{+}} \frac{\sin\left(s\tan^{-1}t\right)}{\left(1+t^2\right)^{\frac{s}{2}}\left(e^{\pi t}+1\right)} \: dt \qquad &\text{For} \: s\in \mathbb{C} \backslash \left\{1\right\}. \\ \zeta\left(s,q\right) &= \frac{p^{1-s}}{s-1} + 2\int_{\mathbb{R}^{+}} \frac{\sin\left(s\tan^{-1}\left(\frac{t}{q}\right)\right)}{\left(q^2+t^2\right)^{\frac{s}{2}}\left(e^{2\pi t}-1\right)} \: dt \: + \frac{1}{2q^s} \qquad &\text{For} \: \text{Re}\left(q\right) \geq 0. \end{align} $$

Which if we apply to the second definition of $\zeta_k$:

$$ \begin{multline} \zeta_{k}(s)=\frac{2^{s-1}-(k+1)^{s-1}}{s-1}-\frac{1}{2(k+1)^s} \\ -2\int_{\mathbb{R}^+} \frac{2^{s-1}\sin{\left(s\tan^{-1}t\right)}}{(1+t^2)^{s/2}(e^{\pi t}+1)} + \frac{\sin{\left(s\tan^{-1}\left(\frac{t}{k+1}\right)\right)}}{((k+1)^2+t^2)^{s/2}(e^{2\pi t}-1)} \: dt \end{multline} $$

By analytic continuation the formula for the partial sums of the zeta function has been extending from the positive integers to allowing complex arguments.

Is this analytic continuation correct? Also are there any similar analytic continuations involving trig ratios? Any input would be greatly appreciated

  • $\sum_{n=1}^k n^{-s}$ is already entire – reuns Aug 14 '16 at 3:20

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Browse other questions tagged or ask your own question.