0
$\begingroup$

removed - unclear question....

$\endgroup$

closed as off-topic by 6005, ilovetolearn, Leucippus, Claude Leibovici, ervx Aug 11 '16 at 14:51

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – 6005, Claude Leibovici, ervx
If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ Your formatting is off. In the answer, is the $10$ in the numerator or denominator? $\endgroup$ – imranfat Aug 11 '16 at 13:48
  • $\begingroup$ $2\times 5 = 10$ $\endgroup$ – gammatester Aug 11 '16 at 13:49
  • $\begingroup$ What author? What answer? $\endgroup$ – 6005 Aug 11 '16 at 13:49
  • $\begingroup$ 10 is the denominator $\endgroup$ – ilovetolearn Aug 11 '16 at 13:49
  • $\begingroup$ To make stacked fractions, use \frac, so \frac{3}{10} gives $\frac {3}{10}$. You don't need the braces for a single character. Similarly, if you put braces around the stuff that goes under the square root sign, the top bar extends to cover, so \sqrt{(3)} gives $\sqrt {(3)}$ In this case you are just multiplying $\frac 35$ by $\frac 12$ and the $\sqrt 3$ goes along for the ride. $\endgroup$ – Ross Millikan Aug 11 '16 at 13:51
0
$\begingroup$

$$\frac{3}{5}\cdot\frac{\sqrt{3}}{2}=\frac{3}{10}\cdot\sqrt{3}\Longleftrightarrow$$ $$\frac{3\cdot\sqrt{3}}{5\cdot2}=\frac{3}{10}\cdot\sqrt{3}\Longleftrightarrow$$ $$\frac{3\cdot\sqrt{3}}{10}=\frac{3}{10}\cdot\sqrt{3}\Longleftrightarrow$$ $$\frac{3\cdot\sqrt{3}}{10}=\frac{3\cdot\sqrt{3}}{10}$$

Because $2\cdot5=10$.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.