0
$\begingroup$

Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled , on average, 8 miles per hour faster than the other car, what was the average speed of each car for the 2-hour trip?

I have the answer as 48 mph and 56 mph. But, I am not sure how to calculate the Time / Speed / Distance.

$\endgroup$

1 Answer 1

1
$\begingroup$

If the speed of one car is $v$ mph and that of the other $v+8$ mph, then after two hours they will have travelled $2v$ miles and $2v+16$ miles respectively. Hence, solve $$2v+(2v+16)\ =\ 208$$

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .