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How do you form this term that you get $$\frac{3k^{2}+3k}{k^{4}+k^{3}}=\frac{3k}{k^{3}}$$?

I know that both are the same but I don't know how we can get to this... Tried to exclude $k$ but it didn't give me that solution. I'm absolutely sure that $3$ has been excluded to get this but what did you do with the $k's$?

$$3\cdot\frac{k(k+1)}{k(k^{3}+k^{2})}=\frac{3(k+1)}{k^{3}+k^{2}}$$

I could try till tomorrow and no solution, anyone can tell me please?

This is no homework, as all my other questions. I'm asking to understand only.

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  • $\begingroup$ Notice that $k\neq -1$ $\endgroup$
    – Garmekain
    Feb 5, 2019 at 0:18

1 Answer 1

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You can simplify the numerator and denominator: $$\dfrac{3k^{2}+3k}{k^{4}+k^{3}}=\dfrac{3k(k+1)}{k^{3}(k+1)}$$

This is equal to

$$\frac{3k^{2}+3k}{k^{4}+k^{3}}=\frac{3k}{k^{3}}$$

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  • $\begingroup$ Oh alright thanks a lot :) $\endgroup$
    – cnmesr
    Aug 6, 2016 at 11:00

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